コンプリート！ Y'=2xy^2 Y=1/(4-x^2) 219912-Y'=2xy^2 Y=1/(4-x^2)
See the answer See the answer done loading y'=2xy^2;Graph y=1/2*(x4)^22 Find the properties of the given parabola Tap for more steps Use the vertex form, , to determine the values of , , and Since the value of is positive, the parabola opens up Opens Up Find the vertex Find , the distance from the vertex to the focus How do you use Implicit differentiation find #x^2 2xy y^2 x=2# and to find an equation of the tangent line to the curve, at the point (1,2)? X2 Y 1 Dx Y2 X 1 Dy 0 41 Pages Solution Doc 1 3mb Updated Alaina Books Chapter Y'=2xy^2 y=1/(4-x^2)